Clean up 'print_fn_descriptor_symbol()' types

Everybody wants to pass it a function pointer, and in fact, that is what
you _must_ pass it for it to make sense (since it knows that ia64 and
ppc64 use descriptors for function pointers and fetches the actual
address from there).

So don't make the argument be a 'unsigned long' and force everybody to
add a cast.

Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>

1 files changed, 14 insertions, 10 deletions

diff --git a/include/linux/kallsyms.h b/include/linux/kallsyms.h
index 82de2fb62cb..00c1801099f 100644
--- a/include/linux/kallsyms.h
+++ b/include/linux/kallsyms.h
@@ -83,16 +83,6 @@ __attribute__((format(printf,1,2)));
 static inline void __check_printsym_format(const char *fmt, ...)
 {
 }
-/* ia64 and ppc64 use function descriptors, which contain the real address */
-#if defined(CONFIG_IA64) || defined(CONFIG_PPC64)
-#define print_fn_descriptor_symbol(fmt, addr)		\
-do {						\
-	unsigned long *__faddr = (unsigned long*) addr;		\
-	print_symbol(fmt, __faddr[0]);		\
-} while (0)
-#else
-#define print_fn_descriptor_symbol(fmt, addr) print_symbol(fmt, addr)
-#endif
 
 static inline void print_symbol(const char *fmt, unsigned long addr)
 {
@@ -101,6 +91,20 @@ static inline void print_symbol(const char *fmt, unsigned long addr)
 		       __builtin_extract_return_addr((void *)addr));
 }
 
+/*
+ * Pretty-print a function pointer.
+ *
+ * ia64 and ppc64 function pointers are really function descriptors,
+ * which contain a pointer the real address.
+ */
+static inline void print_fn_descriptor_symbol(const char *fmt, void *addr)
+{
+#if defined(CONFIG_IA64) || defined(CONFIG_PPC64)
+	addr = *(void **)addr;
+#endif
+	print_symbol(fmt, (unsigned long)addr);
+}
+
 #ifndef CONFIG_64BIT
 #define print_ip_sym(ip)		\
 do {					\